portlet access control by user role

[12年前 に shahab mahtab によって更新されました。]

Hi:

I would like to grant access to a portlet ("add to page" and "view") based on few custom roles only, which are imported from LDAP.
I have defined the roles in portlet.xml and liferay-portlet.xml of the portlet.

However, it looks like any user can view the portlet. What is the correct way to enforce it?

I have tried adding the permission file (resource-actions\....xml). I can restrict guests from viewing the portlet this way. But, it looks like "resource-action-mapping" DTD does not support custom roles.

Is there a way to enfore role based access control without using the built-in Permissions GUI?

Thanks.

[12年前 に David H Nebinger によって更新されました。]

Sure...

Drop the portlet on the page, go to the configuration page for the portlet, to the permissions tab, and set the permissions there. Disable guest perms on the portlet, and you should be golden...

[12年前 に shahab mahtab によって更新されました。]

Hi:

Can I configure it from any configuration file other than the "Permissions" tab?

Thanks

[11年前 に Mauro Almeida によって更新されました。]

Hi Shahab.

Did you manage to overcome this?

Best regards,
MJA

[11年前 に Thomas Berg によって更新されました。]

Hello Shahab,
You should be able to achieve what you need by reading the information in this thread

HTH

Regards / Thomas

[11年前 に shahab mahtab によって更新されました。]

Hi HTH,

I believe, resource-action-mapping takes some pre-defined roles only (guest, community etc.). I ended up writing a filter to checks user's role, and show appropriate message if user is not authorized.

My use case is slightly different. Users are accessing some pre-configured pages with bunch of portlets, and they can view portlets that they are entitled to. (users' entitlement can change dynamically)

Thanks
Shahab

[9年前 に Pablo Martin によって更新されました。]

Hi,

I have 2 instances on my liferay
and some portlets deployment and list of portlets in dockbar on adding cannot be seen to another neither the administrator of the another instance.

create a hook to some .jsp is it good ?
How i suppose to do that?

Regards,
Pablo M.